If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-7x+36=(2x-11)(x+2)
We move all terms to the left:
4x^2-7x+36-((2x-11)(x+2))=0
We multiply parentheses ..
4x^2-((+2x^2+4x-11x-22))-7x+36=0
We calculate terms in parentheses: -((+2x^2+4x-11x-22)), so:We add all the numbers together, and all the variables
(+2x^2+4x-11x-22)
We get rid of parentheses
2x^2+4x-11x-22
We add all the numbers together, and all the variables
2x^2-7x-22
Back to the equation:
-(2x^2-7x-22)
4x^2-7x-(2x^2-7x-22)+36=0
We get rid of parentheses
4x^2-2x^2-7x+7x+22+36=0
We add all the numbers together, and all the variables
2x^2+58=0
a = 2; b = 0; c = +58;
Δ = b2-4ac
Δ = 02-4·2·58
Δ = -464
Delta is less than zero, so there is no solution for the equation
| g+12=8 | | 4=n1.04 | | (2x-4)^2-12=0 | | (x)=6⋅x+5 | | 13+5p=7 | | 2(4-5n)-5n=9n | | 5(a+1)=90 | | 2a-1/2=3 | | 2c+2=4c | | x=-(32)±√(32)²-4(1)(-200)÷2(1) | | 4-2p+3=3p+1-p | | 5(2a-3)=6(2a+111 | | 2/3(6x+9)+2x-5=3(x-2)+1/2(2x-4) | | (2)/(3)(6x+9)+2x-5=3(x-2)+(1)/(2)(2x-4) | | 5x=√3x+4 | | 2x+4=3x(x-2) | | x*5=1,05 | | 3x-40=-120 | | r/10=17 | | 2/3(6x+9)+2x−5=3(x−2)+12(2x−4) | | (2x-4)^2=12 | | 83^x=1/9 | | 〖83〗^x=1/9 | | 1/4+1/8a=1/2 | | -10b=150 | | 4^(x+2)=16 | | 5t-8=17 | | 2y=-8×+9 | | 10=0.25t-5 | | 60+12b=0 | | (2x+6)/8=7 | | (8x)/2=48 |